45r^2=5r

Solution for 45r^2=5r equation:

45r^2=5r

We move all terms to the left:

45r^2-(5r)=0

a = 45; b = -5; c = 0;
Δ = b2-4ac
Δ = -52-4·45·0
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{25}=5$
$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-5}{2*45}=\frac{0}{90}
=0
$
$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+5}{2*45}=\frac{10}{90}
=1/9
$